Determine percent by m?

You should determine the molecular weight of sulfuric acid first. Use the values in your textbook to determine this. I got 98.07848 g/mol. Since you have 1.49 M solution of sulfuric acid, this means 1.49 mols/L of solution. Knowing this, you can multiply 1.49 by 98.07848 to give 146.137 g of acid/L of water. Its usually umed that 1 L of water = 1kg, so divide by 1000g ( you want the same units) to give you 0.146. Multiply this by 100%, and you have 14.6% sulfuric acid by m.